(4x^2-2x+1)+(2x+8)=

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Solution for (4x^2-2x+1)+(2x+8)= equation:


Simplifying
(4x2 + -2x + 1) + (2x + 8) = 0

Reorder the terms:
(1 + -2x + 4x2) + (2x + 8) = 0

Remove parenthesis around (1 + -2x + 4x2)
1 + -2x + 4x2 + (2x + 8) = 0

Reorder the terms:
1 + -2x + 4x2 + (8 + 2x) = 0

Remove parenthesis around (8 + 2x)
1 + -2x + 4x2 + 8 + 2x = 0

Reorder the terms:
1 + 8 + -2x + 2x + 4x2 = 0

Combine like terms: 1 + 8 = 9
9 + -2x + 2x + 4x2 = 0

Combine like terms: -2x + 2x = 0
9 + 0 + 4x2 = 0
9 + 4x2 = 0

Solving
9 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 4x2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 4x2 = 0 + -9
4x2 = 0 + -9

Combine like terms: 0 + -9 = -9
4x2 = -9

Divide each side by '4'.
x2 = -2.25

Simplifying
x2 = -2.25

Reorder the terms:
2.25 + x2 = -2.25 + 2.25

Combine like terms: -2.25 + 2.25 = 0.00
2.25 + x2 = 0.00

The solution to this equation could not be determined.

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